, you participated in the previous thread where we posted a crude calculation of what I called the "power to the wheels".
The yellow curve you ask for, comes from this calculations, using essentially the same equations Scotracer used.
I pasted a section of the graph of speed vs time in AutoCAD. Then I traced vertical black lines every second. I callibrated the scale and with the coordinates of the points on the graph every second, I got the speed, like this:
From that figures I estimated the power to the wheels, using a frontal area and a drag coefficient. This were the results posted in that thread:
The yellow line is a graph of that estimation of total power to the wheels, that is, row 22 in the previous picture.
This gives an answer to your question. You can see that, when the car is at low speeds, most of the power is used to overcome inertia (that is, to move the damn car). At high speeds most of the power is used to overcome drag. The force at low speeds is around 700 kilograms. If you repeat the calculations at lower speeds (one of the peaks go down to 70 kph or so), you might get 900 kg, tops.Autogyro
: the tyres slip to move the car, in the sense explained in this thread, something you probably know: Must a tire slip to generate force?
I think this limits the acceleration you can give to the car, CVT or not. That 2.5 mu coefficient Jersey Tom is talking about is only to move the car laterally.
This means that even if you cannot see it the tyre is sliding "under the patch" to propel the car ahead. The ultimate power you can deliver to move ahead the car, the thrust that xpensive asks for, is limited by that "inner friction", invisible: anyway you won't get over 1.5 Gs, I think.
The 2.5 mu that JTom mentions only works to move laterally the car. You can easily see from Reca's graph, from the top of your head, that when the car is accelerating, it's not limited by the gearbox, but by the rubber, if you follow my drift.