freedom_honda wrote:I've heard that the BrawnGP gearbox was over-torqued at the start. Can anyone explain what does it mean by "over-torqued"?
This is just a representative picture, but the components are the same as in a Formula One car. If the output from the engine is at (let's just pick any number at random to make things easy) 500 ft-lbs, and if the gear ratio between the engine output shaft and the layshaft is 1:1, then the torque experienced at the layshaft is also 500 ft-lbs. If the layshaft is geared at half the speed of the engine, then because of mechanical ratios, the torque at the layshaft is (500x2) 1000 ft-lbs.
This mechanical ratio applies to all components in the drivetrain. Now examine first gear, and let's assume the gear ratio between the layshaft and output shaft is 1:4. If the input torque is 500 ft-lbs, then the output torque is (500x4) 2000 ft-lbs. Now let's take a shortcut and examine the 7th (top) gear. For simplicity's sake let's assume the final drive ratio is 2:1. Now, the output torque is (500/2) 250 ft-lbs.
Due to the ratios in the gearbox, the output torque is relative to the ratio. How this applies to the drivetrain is that at lower gears, the torque experienced by the output shaft is high, then progressivley lowers as the gear ratio climbs.
This also applies to driving in slippery conditions, especially snow. I tell all my friends driving manual transmissions to always use one gear higher than normal in the snow to lessen the torque at the rear wheels. That way the drive wheels are less likely to slip and lose traction.
A proud Canadian, and yes, HOCKEY is our game.