Fair enough.henry wrote: ↑Sat Aug 08, 2020 7:02 pmThe equation is
Engine power(kW) = ( Q(kg/h) - 22.85) / 0.257
a flow, Q, of 10kg/hr gives -50kW As specified
So it’s not mistranslation or a typo. It really is minus50kW
Still I take it as an equation for a rule. Not as a direct a physical relationship between fuel injected and net energy flow of the engine.
Unless the teams advance timing so much that the combustion is pushing against the piston as it rises up the compression stroke, the combustion should always be a net positive energy flow to the engine or else it would be wasteful.
Other losses that create subtractive energy flows. Pumping, Compression, inertia, friction etc. I think should be sufficient for engine braking?
Again i feel this rule is not to limit the propulsion or engine braking power by the fuel injected. This is to stop other tricks that can be done with fuel.