I think tthe main problem of this discussion about tire usage and power on the Merc is, that the max torque and the max power are not directly related to each other. The max power of the ICE is simply restricted by its fuel efficiency, while the torque is not.FoxHound wrote: My bet is the Mercedes is more powerful in both torque figures and bhp. And as the simplest definition(there's a thread on this...lots of opinions) for the relation is Power = the rate at which bhp delivers it's torque. Explained to me by a Honda technician(Yuasa racing).... A diesel has 200nm torque and can deliver that at a rate of 150bhp, versus a Petrol with 120nm torque that can deliver it at 170bhp. The diesel would be superior if the cars were of similar mass, size etc.
I do not think these values for power and torque are real. The MGU-K alone delivers 200Nm, so realistic values would be either 500Nm for the ICE alone or if you take MGU-K and ICE together to get the 900bhp, the torque should be much higher.FoxHound wrote: Well the V6 Turbo's are pushing near 500nm Torque and around 900bhp all told(with recuperated energy).
No engine revs close to the maximum of 15k, but closer to 12k due to the fuel flow restriction.
The engine's torque is nigh on instantaneously available, as evidence from 2014 depicts, right through the rev range to 12k.
No. The engine max power has nothing to do with the tire. It is the power vs rev curve, which needs to be flat.FoxHound wrote: Bear this in mind, because now we have the tyre dealing with this torque. The tyres are the same for everyone, and the top 3 are within about 20bhp or so(torque figures for the turbo's are hard to come by).
Would it not stand to reason that a more powerful engine would be breaking traction more easily through the tyre?
I guess it's not practical because of how bad combustion engines are at converting energy to work.SameSame wrote:Because the energy is converted from linear (in the piston) to rotational energy (in the crankshaft). I don't think it would be possible to measure torque at the piston seeing as the piston moves linearly.
Hmm, makes you wonder how much torque is a result of the inertia in the crankshaft mass, vs the rest of the combustion process. Afterall, it's the inertia in the crank that allows a single piston 4t engine to work.Jolle wrote:The force per piston is also very measurable or can be worked out from the power from an engine. I do believe that is what, when building an engine is being designed, is one of the things they are working with. But if the force on all pistons is combined in an easy to measure and compare between different engines (even the ones without pistons) what is the point?
Plus, torque in a piston engine is (to make it even more difficult) average torque, in a 4t engine, over two revolutions. If you take a one cylinder engine for instance, there is just a push for ¼ of the time, ½ nothing and ¼ "negative" push (compression).
Inertia has no result on the torque what so ever. Please re-read about what torque and power are. When a mass is moving or spinning, without a change of direction or speed, no force is present.godlameroso wrote:I guess it's not practical because of how bad combustion engines are at converting energy to work.SameSame wrote:Because the energy is converted from linear (in the piston) to rotational energy (in the crankshaft). I don't think it would be possible to measure torque at the piston seeing as the piston moves linearly.
Hmm, makes you wonder how much torque is a result of the inertia in the crankshaft mass, vs the rest of the combustion process. Afterall, it's the inertia in the crank that allows a single piston 4t engine to work.Jolle wrote:The force per piston is also very measurable or can be worked out from the power from an engine. I do believe that is what, when building an engine is being designed, is one of the things they are working with. But if the force on all pistons is combined in an easy to measure and compare between different engines (even the ones without pistons) what is the point?
Plus, torque in a piston engine is (to make it even more difficult) average torque, in a 4t engine, over two revolutions. If you take a one cylinder engine for instance, there is just a push for ¼ of the time, ½ nothing and ¼ "negative" push (compression).
There are centripetal forces present in any rotating object....Jolle wrote:Inertia has no result on the torque what so ever. Please re-read about what torque and power are. When a mass is moving or spinning, without a change of direction or speed, no force is present.godlameroso wrote:I guess it's not practical because of how bad combustion engines are at converting energy to work.SameSame wrote:Because the energy is converted from linear (in the piston) to rotational energy (in the crankshaft). I don't think it would be possible to measure torque at the piston seeing as the piston moves linearly.
Hmm, makes you wonder how much torque is a result of the inertia in the crankshaft mass, vs the rest of the combustion process. Afterall, it's the inertia in the crank that allows a single piston 4t engine to work.Jolle wrote:The force per piston is also very measurable or can be worked out from the power from an engine. I do believe that is what, when building an engine is being designed, is one of the things they are working with. But if the force on all pistons is combined in an easy to measure and compare between different engines (even the ones without pistons) what is the point?
Plus, torque in a piston engine is (to make it even more difficult) average torque, in a 4t engine, over two revolutions. If you take a one cylinder engine for instance, there is just a push for ¼ of the time, ½ nothing and ¼ "negative" push (compression).
THEY ARE NOT DIRECTLY CONVERTEDSameSame wrote: Edit: The point is to fundamentally understand the concept. Work (which is a force (N) performed over a distance (m) is measured in Joules). So they are literally directly converted. Do not read some article and just stick by one line, rather try to understand how basic physics concepts work.
As I mentioned before I meant to say net torque (that's what I corrected Tim with). If an object has a net torque the torque will act through an angle.PhillipM wrote:THEY ARE NOT DIRECTLY CONVERTEDSameSame wrote: Edit: The point is to fundamentally understand the concept. Work (which is a force (N) performed over a distance (m) is measured in Joules). So they are literally directly converted. Do not read some article and just stick by one line, rather try to understand how basic physics concepts work.
Which is what everyone is trying to get past you. Work, or energy, is a force (N) applied through a distance (m) traveled, which is Joules. As you say.
Torque is a force (N) applied at a distance (m). It IS NOT a force going through a distance. If whatever you're applying the torque to doesn't move then there is no energy.
That is why the units are not interchangable. It matters how you get there.
And there is some tension between the engineer and his wife but that has nothing to do with torque, power or inertia.SameSame wrote:There are centripetal forces present in any rotating object....Jolle wrote:Inertia has no result on the torque what so ever. Please re-read about what torque and power are. When a mass is moving or spinning, without a change of direction or speed, no force is present.godlameroso wrote:
I guess it's not practical because of how bad combustion engines are at converting energy to work.
Hmm, makes you wonder how much torque is a result of the inertia in the crankshaft mass, vs the rest of the combustion process. Afterall, it's the inertia in the crank that allows a single piston 4t engine to work.
Again you're almost right but also wrong. A spinning mass has an inertia energy stored inside it's mass and movement. A spinning object also experience rotational force.SameSame wrote:Centripetal forces have everything to do with inertia… A massless object would experience no cevtripitel force![]()
Or my sense of humor has taken a nose dive after a long day
I believe this was covered before.SameSame wrote:I never said they were interchangeable…
In power, N.m is converted to J for convinience sake…
I was also told a radian is not dimensionless…
My point was that N.m/s is expressed as J/s. Look how power is derived.
https://en.wikipedia.org/wiki/RadianRadian describes the plane angle subtended by a circular arc as the length of the arc divided by the radius of the arc. One radian is the angle subtended at the center of a circle by an arc that is equal in length to the radius of the circle. More generally, the magnitude in radians of such a subtended angle is equal to the ratio of the arc length to the radius of the circle; that is, θ = s / r, where θ is the subtended angle in radians, s is arc length, and r is radius. Conversely, the length of the enclosed arc is equal to the radius multiplied by the magnitude of the angle in radians; that is, s = rθ.